Hi Lynda!
You problem is spot on for practicing addition and subtraction using complements of 10. Your instructions are short and sweet but I bet students would like it that way.
Hi Melissa!
Your problem does have an addition complement of 10. Nice work. I see you explained your own problem in #3 (sort of). In your instructions for your own problem you do not indicate removing the 5 bead from the ones column after you set the one bead in the ten’s column.
Do you want to try writing a script describing the steps of adding nine to six?
I am not a teacher yet but I feel like a calculator wasn’t introduced to me until middle school or late elementary.
7 + 3  5 + 6  2
Start with 7
Add 3: 7+3=10
7+3=10 (This demonstrates the complement of 7 and 3 making 10)
Subtract 5: 10−5=5
Add 6: 5+6=11
Subtract 2: 11−2=9
Final result: 9
Hi nieberding.28, your problem is actually quite complex with multiple complementary number movements. At this time you and your student have only learned the complements of 10. I suggest 7 + 3 + 5 + 3  2 so your student has more success.
Hi appleton.thea, would you still wait until sixth grade to introduce the abacus?
Your problem is a great introduction to the complements of 10 for your student.
Ooops! That was a mistype!
I start showing them a basic abacus in preschool for counting. We work on abacus a lot more in elementary, and some students choose to use it in class. Some students fight it. I introduced a talking calculator to my students at a young age, as a way to check calculations done on their braille writer or abacus. However, I didn’t provide them a TALKING CALCULATOR to use atwill in class until the same time as their peers  about 5th or 6th grade. I don’t think I would change when I teach these skills.
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I’m not a teacher, but I believe I started using calculators the beginning of 6th grade.

6+1+1+91

Write a script describing the steps of adding nine to six.
Set up the number 6 (5 bead & 1 bead)
Add 1 extra bead
Add another 1 bead
To add the 9, we will have to look at the tens column and push up 1 ten bead. We must remember the complement number of 10 and 9, which is 1. We will push down 1 bead from the ones column.
Lastly, we will remove 1 bead.
We are left with 10 and 6, and the total would be 16.
Hi mohamoud.25!
Your problem is a great starting problem to introduce the complementary addition of 9 and 1.
The first two steps in your directions for adding nine and six are unusual. I am not sure why you are doing these parts: ‘add 1 extra bead; add another 1 bead’
In addition, your last step, ‘lastly, we will remove 1 bead’ seems unnecessary. With all of these unneeded steps, you have come to the wrong answer of 16. The answer should be 15.
The only directions you need are:
Set up the number 6 (5 bead & 1 bead)
To add the 9, we will have to look at the tens column and push up 1 ten bead. We must remember the complement number of 10 and 9, which is 1. We will push down 1 bead from the ones column.